How do I solve the mathematics problem x (4x^2+3) / (2x+1) ^3=7?

 To solve the equation x(4x^2+3)/(2x+1)^3 = 7, we can follow these steps:


1. Simplify the denominator by expanding (2x+1)^3 using the binomial formula:

(2x+1)^3 = 8x^3 + 12x^2 + 6x + 1


2. Substitute this expression and simplify the numerator:

x(4x^2+3)/(8x^3+12x^2+6x+1) = 7


4x^3 + 3x = 56x^3 + 84x^2 + 42x + 7


52x^3 + 84x^2 + 39x - 7 = 0


3. Factor the polynomial. Since there are no obvious common factors, we can use numerical methods or the rational root theorem to find a root. One possible root is x = 1/2:

52(1/2)^3 + 84(1/2)^2 + 39(1/2) - 7 = 0


13 + 21 + 39/2 - 7 = 0


So x = 1/2 is a root of the polynomial.


4. Divide the polynomial by x - 1/2 to obtain a quadratic factor. We can use polynomial division or synthetic division to do this. The result is:

52x^2 + 105x + 14 = 0


5. Solve the quadratic equation using the quadratic formula or factoring. The solutions are:

x = (-105 ± sqrt(105^2 - 4(52)(14))) / (2(52))


x = (-105 ± sqrt(11041)) / 104


x = (-105 ± 105) / 104 or x = (-105 ± sqrt(11041)) / 104


x = -1 or x ≈ 0.1417 or x ≈ -1.6276


Therefore, the solutions to the equation x(4x^2+3)/(2x+1)^3 = 7 are x = -1, x ≈ 0.1417, and x ≈ -1.6276.

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